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0=0.25d^2-100
We move all terms to the left:
0-(0.25d^2-100)=0
We add all the numbers together, and all the variables
-(0.25d^2-100)=0
We get rid of parentheses
-0.25d^2+100=0
a = -0.25; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-0.25)·100
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*-0.25}=\frac{-10}{-0.5} =+20 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*-0.25}=\frac{10}{-0.5} =-20 $
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